3x^2+18x=147

Solution for 3x^2+18x=147 equation:

3x^2+18x=147

We move all terms to the left:

3x^2+18x-(147)=0

a = 3; b = 18; c = -147;
Δ = b2-4ac
Δ = 182-4·3·(-147)
Δ = 2088
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2088}=\sqrt{36*58}=\sqrt{36}*\sqrt{58}=6\sqrt{58}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-6\sqrt{58}}{2*3}=\frac{-18-6\sqrt{58}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+6\sqrt{58}}{2*3}=\frac{-18+6\sqrt{58}}{6}
$